35=p^2-3p/2

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Solution for 35=p^2-3p/2 equation: 


p in (-oo:+oo)

35 = p^2-((3*p)/2) // - p^2-((3*p)/2)

(3*p)/2-p^2+35 = 0

3/2*p-p^2+35 = 0

DELTA = (3/2)^2-(-1*4*35)

DELTA = 569/4

DELTA > 0

p = ((569/4)^(1/2)-3/2)/(-1*2) or p = (-(569/4)^(1/2)-3/2)/(-1*2)

p = ((569/4)^(1/2)-3/2)/(-2) or p = ((569/4)^(1/2)+3/2)/2

p in { ((569/4)^(1/2)-3/2)/(-2), ((569/4)^(1/2)+3/2)/2 }

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